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[智力答题] (转)一组高中学生电脑编程竞赛试题

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    慵懒
    2020-12-25 07:11
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    发表于 2020-11-27 11:55 | 显示全部楼层 |阅读模式

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    紫荆棘鸟注:继续活跃气愤,给大家一组美帝高中生电脑编程竞赛试题,活动活动脑细胞。

    美帝许多名牌大学和大规模的公立大学会经常举办一些电脑编程竞赛,一般分高中生和本科生两个档次,这些竞赛有个统一的名称:hack-a-thorn,意思就是挑刺比赛。为了不影响学习,这些比赛通常会在周末举办,或者假期(特别是长长的暑假)举办。参赛者一般都是自愿的,参赛者所在的学校一般不会出面组织。一般优秀的高中生和低年级的大学生会报名参加,取得好名次的学生会得到些小奖品,这些奖品一般都是些比较时尚的东西,例如微型电脑、健身手表、耳机等。当然,竞赛取得名次最好的奖励还是可以写进个人简历,这对学生找暑假实习机会(internships)会有很大的好处。

    举办方一般会提供食宿安排:吃饭一般是免费的,美帝的食物很便宜,能养肥海量的大胖子;住宿:举办方一般提供些大礼堂或者空置的宿舍,参赛学生们自带睡袋。当然,竞赛完后如果还有时间,举办方还会安排一些到附近观光游览的小活动。参赛者可以自己开车去参赛(如果不远的话),也可以去附近的大学(特别是大规模的大学)搭乘巴士。当然这些都是免费的,美国有许多义工热衷于公益活动。如果参赛的地方比较远(例如加州或者加拿大的高校),需要搭乘飞机,机票也有可能是免费的,有些公司会赞助这些活动。

    楼下的试题就是宾夕法尼亚大学(Univ of Pennsylvania)某年举办的中学生电脑竞赛试题。一共九个题,时间是四小时,可以组队参赛,也可以单独参赛。组队不限人数,但只能有一台电脑。每题满分 1 分,答错计 0 分,答对计 1 分。如果两队得分一样,那么评委将根据答错的题回答的情况计小分,以决定名次。试题是俺弄来的,至于怎么弄来的这里就没必要说了。宾大在美帝是八所常青藤院校之一,医学院、商学院等在美帝是数一数二的,但计算机专业不属于一流水平。

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     楼主| 发表于 2020-11-27 11:55 | 显示全部楼层
    Philadelphia Classic 2013
    Hosted by the Dining Philosophers
    University of Pennsylvania

    Basic rules:
    4 hours, 9 problems, 1 computer per team
    You can only use the internet for accessing the Javadocs, and for PC^2 (to submit your solutions)
    Do not modify any of the given methods! They are all specified in the desired format. There is no penalty for incorrect submissions. You will receive 1 point per problem solved. Number of incorrect submissions will be used only as a tiebreaker.

    1. Anagrams
    In the game Anagrams, you start with a random 3 letter word. To generate longer words, you take the 3-letter word, potentially scramble the letters in the word, and add a letter. For example, CAT could generate CATS, TACK, or PACT. Define a Sequence to be a list of words, [n1, n2, …, nk] such that 1) the first word (n1) is 3 letters long, and 2) n1 generates n2, n2 generates n3, etc. Define an “n-Sequence” to be a sequence that ends with an n-letter word? i.e. [CAT, PACT, PATCH] is a 5-Sequence.

    Your inputs will be an int, n, a string, k, and a sorted list of words representing the dictionary. You can assume that the words in the dictionary are all between length 3 and 8, and consist only of uppercase letters (no hyphens, etc). The dictionary we will be testing with is included in your files as dictionary.txt, and in the main method, we read it into memory.

    k will be a 3-letter word from the dictionary, and n will be between 4 and 8. Return the number of n-Sequences that start with k.

    Sample Input:
    (1): 4, CAT
    (2): 5, DOG

    Sample Output:
    (1): 18 (the 18 words generated by CAT are ACTA, ACTS, CANT, CART, CAST, CATE, CATS,
    CHAT, COAT, FACT, PACT, SCAT, TACE, TACH, TACK, TACO, TACT, TALC)
    (2): 58

    2. Palindrome Search
    Write a program which finds the longest palindromic substring of a given string. A substring is considered palindromic if reversing the order of the characters in the string results in the same string. (As a note, “a” “ab” are two of the substrings of “abc” but “ac” is not)

    Sample Input:
    The input will be a string containing at least one palindromic substring of length > 1. You can assume that will consist only of lowercase letters.
    (1): “youdontwanttomissracecarsspeedingaroundthetrack”
    (2): “ababbabababaaababaabbaa”

    Sample Output:
    Output the longest palindromic substring of the input string. If there are multiple such substrings of equal length, output the first one.
    (1): “ssracecarss”
    (2): “ababaaababa”

    3. Circular Primes
    Write a program which determines whether a given number is a “circular prime”. A number is considered a circular prime if and only if each number created by rotating its base 10 digits is prime. For example, 113 is considered a circular prime because 113, 131, and 311 are all prime.

    Sample Input:
    The input will be a number of type long. You can assume that numbers given as inputs
    are greater than 1.
    (1): 8675309
    (2): 2
    (3): 11

    Sample Output:
    Output the Boolean value true if the number is a circular prime? false if not.
    (1): false
    (2): true
    (3): true

    4. Sum of Digits in Bases
    You may be familiar with representation of numbers in different “bases”. The standard numeric system is the “decimal” system, or base 10. Another well-known system is binary, or base 2. When counting in base N, each digit can have a maximum value of N1 (so in base 10, the maximum digit value is 9? in base 2, each digit can only be 0 or 1). For bases greater than 10, such as base 16, the digits A, B, C, D, E, and F represent values from 10 to 15.

    The concept of sum of digits of a number can easily be extended to any base. If you have the number “AC3” in base 14, for example, the sum of digits should be treated as 10 (A) + 12 (C) + 3 = 25.

    Define a “P-Q-overlap” to be a number which has the same sum of digits in base P and base Q. For example, 75 can be represented as 2210 base 3, and 203 base 6. Since it has a sum of digits of 5 in both bases, it is a 3-6-overlap.

    In this problem, you will be given an input, N. Your task is to determine, which pair of bases P and Q, between 2 and 16 (inclusive), have the maximum P-Q-overlaps over the set of integers from 1 and N, inclusive. If there are more than 1 such pairs P, Q, choose the pair with the highest value of P (where P < Q).

    Sample Input
    (1): 3
    (2): 37

    Sample Output
    If your pair of bases are P and Q, with P < Q, return 100 * Q + P.
    (1): 1615
    (2): 1508

    5. Texas Hold ‘Em
    Texas Hold ‘Em is a common form of poker. From a standard 52 card deck, players are each dealt two cards face down (called their “pocket”), and then five cards are placed face up in the “community”. Of the seven cards that each player has to choose from (2 pocket + 5 community), he picks the strongest five-card
    combination: these five cards make up his “hand”? the player with the best five-card hand wins that game. Any other cards not in the hand do not affect its ranking.

    The following rules determine the ranking of hands:
    ● Ace is the highest-ranking individual card, and 2 is the lowest.
    ● Suits do not have an associated value/ranking. They are only used to determine whether a hand forms a flush.
    ● A flush is a hand which contains five cards of the same suit.
    ● A straight is a hand which contains five cards in sequential rank, e.g. 34567. For straights, Ace can serve as the lowest (A-2-3-4-5) or highest card (10-J-Q-K-A), but you cannot wrap around (K-A-2-3-4 is not a straight).
    ● The ranking of hands is done in categories any hand in one category beats any hand in a lower category. The categories are ordered below, and include the method of ranking hands in the same category.
    ● Some categories (such as four of a kind, pair, etc) are specified by fewer than five cards (whereas a straight and full house are specified by all five cards in the hand)? the additional cards in the hand are called “kickers”.
    1. Straight flush: A hand with five cards of the same suit in sequence. Two such hands are compared by their card which is ranked highest (a A2345 straight flush is lower than a 23456 straight flush).
    2. Four of a kind: A hand with four cards of the same rank, and any other card (kicker), e.g. 33337.
    Two such hands are compared by the rank of the four of a kind card? if that is the same, they are compared by the rank of the kicker.
    3. Full House: A hand with three cards of one rank and two cards of another rank, e.g. 33322. Two such hands are compared by the rank that has three cards? if that is the same, they are compared by the rank that has two cards. So 33322 defeats 222KK.
    4. Flush: Five cards of the same suit. Flushes are compared by the rank of their highest card? if that is the same, then by their second-highest card? if that is the same, third-highest, etc.
    5. Straight: Five cards in sequence. Like straight flushes, compared by the highest-ranked card.
    6. Three of a kind: A hand with three cards of one rank, and two cards of different ranks (each different from each other), e.g. 77792. Compared by the rank of the three of a kind card? if that is the same, then by the highest kicker? if that is the same, then by the second kicker.
    7. Two Pair: A hand with two cards of one rank, two cards of another rank, and another card of a third rank. Compared by the rank of the highest pair, else the rank of the second pair, else by the kicker.
    8. One Pair: A hand with two cards of one rank, and three cards of different ranks, each different from each other. Compared by the rank of the pair, and then by the kickers in descending order.
    9. High Card: A hand meeting none of the above categories. Compared by the rank of the highest-ranked
    card? if those are equal, then by the second-highest,etc.

    You will be given two players’ pocket cards, and the five cards in the community (you can assume that the cards are all distinct). Each card will be represented as a concatenation of two values, where the first value represents the card rank (2 to 10, J, Q, K, and A) and the last value represents the suit (H, S, C, D). All letters will be in uppercase. For each player and the community, each card will be separated from the other cards by a space, and there will be no leading or trailing spaces.

    Your task is to determine whether player 1 has a better hand than player 2.

    Sample Input:
    (1):
    Player 1: AH AS
    Player 2: AD AC
    Community: 3H 5H 7H 9H JD
    (2):
    Player 1: 7H 4C
    Player 2: AD 7C
    Community: AH QS 5H QD JH

    Sample Output:
    (1): true
    (2): false

    6. Spiral Diagonal
    Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows:
              21 22  23 24 25
               20   7   8   9 10
               19   6   1   2 11
               18   5   4   3 12
               17 16 15  14 13

    It can be verified that the sum of the numbers on the diagonal from the upper left to the bottom right is 45. Determine the sum of the numbers on the diagonal from the upper left to the bottom right of a N by N spiral formed in the same way.

    Sample Input
    The input will be the number N. N is guaranteed to be odd.
    (1): 5
    (2): 3

    Sample Output
    (1): 45
    (2): 11

    7. Lucky Numbers
    In number theory, a lucky number is a natural number generated by a “sieve”, a type of sequence-generating operation. You start with the set of odd positive integers, and remove every nth number, where n is the next surviving number in the sequence. This process is repeated over and over ad infinitum. 1 is skipped, for obvious reasons, so n begins with n = 3.

    Start with the set of set of odd numbers: 1,3,5,7,9,11,13,15,17,19,21...
    The next surviving number is 3, so n = 3, and every third remaining number is eliminated.
    Set after removing every third number 1,3,7,9,13,15,19,21...
    The next surviving number is 7, so n = 7, and every seventh remaining number is eliminated.
    Set after removing every seventh number: 1,3,7,9,13,15,21......and so on.
    A number is lucky if it is never removed from the set.

    Sample Input
    The input will be a number of type int, and will be less than 2 million.
    (1): 1
    (2): 19
    (3): 21
    (4): 808342

    Sample Output
    Return a boolean indicating if the given integer is considered lucky.
    (1): true
    (2): false
    (3): true
    (4): false

    8. Equation Solver
    In this problem, we will ask you to implement a basic equation solver. Don’t worry it’s only of one variable, and the maximum degree of the equation is two. Your input will be a string which contains the equation. Terms will be separated from operators (+, , or =) by spaces, but each term will not have any spaces in it. Each term can have an integer coefficient, and an x term, which can be to the first power (no exponentiation) or the second power. The “^” (carat) symbol will be used to denote exponentiation of the x term. A possible input is:
    “3x^2 + x + 3 = 3 + 5x^2 + 7x”.
    You must be able to solve for x for all equations of this form. There may be multiple terms of the same degree on one side of the equation. You can assume that the equation will have a solution? if there is more than one solution, output the greater of the two solutions, rounded to the nearest integer.

    Sample Input
    (1): “3x^2 + x + 3 = 3 + 5x^2 + 7x”
    (2): “5x + x 37 = 0”

    Sample Output
    (1): 4
    (2): 6

    9. Next!
    Given a set of digits {1, 2, …, n}, we can generate a list of all n-digit numbers that use each of those digits exactly once. If n = 3, the set of such numbers is {123, 132, 213, 231, 312, 321}. It is straightforward to order these numbers numerically. For this problem, your challenge is, given one number in this list, to generate the next largest element in the list. You can assume that you will not be given the largest element in the list.

    Sample Input:
    You will be given a string representing a “number”, up to 30 digits long (for n > 10, use A = 10, B = 11, C = 12, D = 13, E = 14, F = 15, G = 16, H = 17, I = 18, J = 19, K = 20, L = 21, M = 22, N = 23, O = 24, P = 25, Q = 26, R = 27, S = 28, T = 29, U = 30). All digits in the number will be distinct. All letters will be in uppercase.
    (1): 132
    (2): 123456789ABCDEFGHIJK
    (3): 35241

    Sample Output:
    (1): 213
    (2): 123456789ABCDEFGHIKJ
    (3): 35412

    珠藏泽自媚,玉韫山含辉。
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    慵懒
    2020-12-25 07:11
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     楼主| 发表于 2020-11-27 11:58 | 显示全部楼层
    Hosted by the Dining Philosophers
    ------------------------------------------------
    注释一下,“dining philosophers” 字面上是就餐的哲学家,但这里实际上是计算机系或者计算机科学的代名词。学过电脑操作系统的人都不会对“哲学家就餐“这个经典问题陌生,因为它可以形象地阐释死锁(deadlock) 以及资源耗尽(starvation)、多线程同步(multi-thread synchronization) 等概念.
    因此这里的 Hosted by dining philosophers 实际上就是(宾大)计算机系举办的意思。
    珠藏泽自媚,玉韫山含辉。
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    发表于 2020-11-27 13:49 | 显示全部楼层
    虽然看着头痛,还是要给你个赞!
    毕竟谜语版许久没有人发帖子了
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    发表于 2020-11-27 14:01 | 显示全部楼层
    看到不是有学校组织,尤其看到住宿甚至要睡睡袋,觉得有意思,苦行僧似的,不像我们这边的学生,参加活动要好吃好喝地招待着,都觉得是理所当然的。
     
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    发表于 2020-11-27 14:02 | 显示全部楼层
    九道题目,4个小时,这些题目肯定很费脑筋。外语不行,题目内容没看懂
     
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    发表于 2020-11-27 14:05 | 显示全部楼层
    最主要不懂计算机专业,解释勉强翻译了字面,应该还是看不懂
     
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     楼主| 发表于 2020-11-27 22:24 | 显示全部楼层
    友昕 发表于 2020-11-27 13:49
    虽然看着头痛,还是要给你个赞!
    毕竟谜语版许久没有人发帖子了

    呵呵,留给那些会电脑编程的人吧,再浪费他们一些脑细胞。
    珠藏泽自媚,玉韫山含辉。
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     楼主| 发表于 2020-11-27 22:42 | 显示全部楼层
    红影 发表于 2020-11-27 14:01
    看到不是有学校组织,尤其看到住宿甚至要睡睡袋,觉得有意思,苦行僧似的,不像我们这边的学生,参加活动要 ...

    毛主席说过,干革命不是请客吃饭。任何人特别是学生们保持一份应有的谦卑,我想是不会有错的。

    举办方一般都是组织得不错的,出题不是什么事,但拉赞助安排食宿等,应该很花时间,一般都是些自愿参加者付出的义务劳动。但参与方是没有学校出面组织,都是学生们自愿报名自己找交通工具去对方学校。
    珠藏泽自媚,玉韫山含辉。
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     楼主| 发表于 2020-11-27 22:46 来自手机 | 显示全部楼层

    СУС
    ве
    珠藏泽自媚,玉韫山含辉。
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     楼主| 发表于 2020-11-27 22:51 | 显示全部楼层
    乱码了。
    四小时做完九道题,基本上不可能,人多也不管用,因为只有一台pc。
    学生们从“题海”中预判并选出适合自己的题,其实也是一种能力。

    对于比较优秀的学生而言,平均一小时做对一道题是没问题的。
    有的题其实很简单,例如第六题,我看就是几分钟的工作量。
    珠藏泽自媚,玉韫山含辉。
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     楼主| 发表于 2020-11-27 22:51 | 显示全部楼层
    乱码了。
    四小时做完九道题,基本上不可能,人多也不管用,因为只有一台pc。
    学生们从“题海”中预判并选出适合自己的题,其实也是一种能力。

    对于比较优秀的学生而言,平均一小时做对一道题是没问题的。
    有的题其实很简单,例如第六题,我看就是几分钟的工作量。
    珠藏泽自媚,玉韫山含辉。
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    发表于 2020-11-28 11:08 | 显示全部楼层
    紫荆棘鸟 发表于 2020-11-27 22:42
    毛主席说过,干革命不是请客吃饭。任何人特别是学生们保持一份应有的谦卑,我想是不会有错的。

    举办方 ...

    这样很好,能培养学生的独立能力。义工也是个很不错的行为,在很多地方能发挥大作用。
     
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    发表于 2020-11-28 11:09 | 显示全部楼层
    紫荆棘鸟 发表于 2020-11-27 22:51
    乱码了。
    四小时做完九道题,基本上不可能,人多也不管用,因为只有一台pc。
    学生们从“题海”中预判并选 ...

    我都看不懂,看来紫荆也是计算机高手呢
     
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     楼主| 发表于 2020-11-29 12:15 | 显示全部楼层
    红影 发表于 2020-11-28 11:09
    我都看不懂,看来紫荆也是计算机高手呢

    电脑高手肯定不是,但知道点简单的编程,工作上也要求一点计算上的编程。
    珠藏泽自媚,玉韫山含辉。
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    发表于 2020-11-29 12:19 | 显示全部楼层
    紫荆棘鸟 发表于 2020-11-29 12:15
    电脑高手肯定不是,但知道点简单的编程,工作上也要求一点计算上的编程。

    那已经很厉害了呢,比我这样的门外汉强很多了
     
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     楼主| 发表于 2020-11-29 12:30 | 显示全部楼层
    红影 发表于 2020-11-29 12:19
    那已经很厉害了呢,比我这样的门外汉强很多了

    呵呵,凭你的 IQ,学点编程,那是小菜一碟。
    珠藏泽自媚,玉韫山含辉。
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     楼主| 发表于 2020-11-29 12:57 | 显示全部楼层
    红影 发表于 2020-11-29 12:19
    那已经很厉害了呢,比我这样的门外汉强很多了

    看这个小程序,试试看:
    http://huachaowang.com/forum.php ... ;tid=43921#lastpost
    珠藏泽自媚,玉韫山含辉。
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    发表于 2020-11-29 15:33 | 显示全部楼层
    紫荆棘鸟 发表于 2020-11-29 12:30
    呵呵,凭你的 IQ,学点编程,那是小菜一碟。

    呵呵,世上的人基本上是用什么,才去学什么的吧,我这人懒,也不能免俗
     
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